-3x(1-4x)-4x^2=0

Solution for -3x(1-4x)-4x^2=0 equation:

-3x(1-4x)-4x^2=0

We add all the numbers together, and all the variables

-4x^2-3x(-4x+1)=0

We multiply parentheses

-4x^2+12x^2-3x=0

We add all the numbers together, and all the variables

8x^2-3x=0

a = 8; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·8·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*8}=\frac{0}{16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*8}=\frac{6}{16}
=3/8
$